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Answered
Conversion to function_handle from double is not possible.
x1=0.1 x2=0.5 x3=5 f(x1)=30.20 f(x2)=7 f(x3)=10.6 x4=x2-0.5*((((x2-x1)^2)*(f(x2)-f(x3)))-((x2-x3^2)*(f(x2)-f(x1)))/(((x2-x...
Conversion to function_handle from double is not possible.
x1=0.1 x2=0.5 x3=5 f(x1)=30.20 f(x2)=7 f(x3)=10.6 x4=x2-0.5*((((x2-x1)^2)*(f(x2)-f(x3)))-((x2-x3^2)*(f(x2)-f(x1)))/(((x2-x...
6 years ago | 0
