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Answered
Given a matrix "A", how to create a row vector of 1s that has the same number of elements as "A" has rows?
A = [1:5; 6:10; 11:15; 16:20]; row_vector=[1 1 1 1 1] col_vector=[1; 1; 1; 1] result=(row_vector*(A'))*(col_vector)
Given a matrix "A", how to create a row vector of 1s that has the same number of elements as "A" has rows?
A = [1:5; 6:10; 11:15; 16:20]; row_vector=[1 1 1 1 1] col_vector=[1; 1; 1; 1] result=(row_vector*(A'))*(col_vector)
5 years ago | 0
