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MATLAB求解非线性方程组的迭代程序。
t=0;x1=[0 0];tol=1; while tol>eps x(1)=(1+x1(2)-0.1*exp(x1(1)))/4; x(2)=(x1(1)-x1(1)^2/8)/4; tol=max(abs(x-x1)); x1=x;t=t+1...
4 years ago | 0
| accepted
