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diwajab


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这个多解超越方程可以用什么方法呢。
把 char E; 去掉。用fsolve可以求解。 应为值域绝大部分是复数,所以不能作图。 fsolve搜索时,需要提供较好的初值。 fsolve(@fun,-7) ans = -6.9905 + 0.0000i fsolve(@fun,-0.1...

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