Statistics
0 Questions
1 Answer
RANK
12,115
of 300,365
REPUTATION
4
CONTRIBUTIONS
0 Questions
1 Answer
ANSWER ACCEPTANCE
0.00%
VOTES RECEIVED
0
RANK
of 20,933
REPUTATION
N/A
AVERAGE RATING
0.00
CONTRIBUTIONS
0 Files
DOWNLOADS
0
ALL TIME DOWNLOADS
0
RANK
of 168,262
CONTRIBUTIONS
0 Problems
0 Solutions
SCORE
0
NUMBER OF BADGES
0
CONTRIBUTIONS
0 Posts
CONTRIBUTIONS
0 Public Channels
AVERAGE RATING
CONTRIBUTIONS
0 Highlights
AVERAGE NO. OF LIKES
Feeds
关于离散点求导数。
是可以用dS/dH=[S(i)-S(i-1)]/[H(i)-H(i-1)]。不过如果你的H(i)-H(i-1)是一个定步长的话，也可以用math老师说的diff函数就可以。
3 years ago | 0
| accepted
