Luca Citi
http://users.neurostat.mit.edu/lciti
Followers: 0 Following: 0
Statistics
All
RANK
277,845
of 300,791
REPUTATION
0
CONTRIBUTIONS
0 Questions
1 Answer
ANSWER ACCEPTANCE
0.00%
VOTES RECEIVED
0
RANK
2,482 of 21,091
REPUTATION
704
AVERAGE RATING
4.70
CONTRIBUTIONS
4 Files
DOWNLOADS
30
ALL TIME DOWNLOADS
6891
RANK
of 171,108
CONTRIBUTIONS
0 Problems
0 Solutions
SCORE
0
NUMBER OF BADGES
0
CONTRIBUTIONS
0 Posts
CONTRIBUTIONS
0 Public Channels
AVERAGE RATING
CONTRIBUTIONS
0 Discussions
AVERAGE NO. OF LIKES
Feeds
Answered
Faster / more precise logarithm of complimentary error function?
Not much faster but certainly more accurate when erfc(x)⩬1: log1p(erf(-x)) So switching between log1p(erf(-x)) and log(erfc(x)...
Faster / more precise logarithm of complimentary error function?
Not much faster but certainly more accurate when erfc(x)⩬1: log1p(erf(-x)) So switching between log1p(erf(-x)) and log(erfc(x)...
2 years ago | 0
