How do you write a matlab function that identifies if a string is a palindrome or not?
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So far I've got ...
string = input('What is your number: '); disp(fliplr(string))
if string == fliplr(string) disp('Your number is a PALINDROME') else disp('Your number is NOT A PALINDROME') end
And now I'm stuck
0 Comments
Accepted Answer
Image Analyst
on 30 Mar 2014
Almost. Try this:
string = input('What is your string: ', 's');
fprintf('Your string = %s\nFlipped, it = %s\n', string, fliplr(string));
if string == fliplr(string)
disp('Your number is a PALINDROME')
else
disp('Your number is NOT A PALINDROME')
end
4 Comments
Star Strider
on 30 Mar 2014
That’s my all time fave!
Probably need to remove all blanks as well before flipping and doing the comparison.
Image Analyst
on 30 Mar 2014
True.
string = lower(string);
string(string == ' ') = '';
More Answers (3)
sesha sai
on 26 Sep 2020
function [ palindromic ] = palindrome( string )
if length(string) < 1
palindromic = logical(1);
return;
end
if string(1) ~= string(length(string))
palindromic = logical(0);
return;
end
palindromic = palindrome(string(2:length(string)-1));
end
1 Comment
Benjamin Askelund
on 19 Oct 2016
Edited: Benjamin Askelund
on 19 Oct 2016
Hi, I made a code that flipps as well NOT USING fliplr based on "Image Analyst" code. Lots of people ask for this as far as I know
clc
%Ask user for string
A = input('What is your string: ', 's');
%flipp string
B = flip(A);
fprintf('Your word = %s\nflipped word is = %s\n', A, B);
%compare stringA and FlippedString (bool)
if strcmp(A, B) == 1
disp('Your number is a PALINDROME')
else
disp('Your number is NOT A PALINDROME')
end
This code also works for numbers. Just type numbers insted of strings
Sorce: https://se.mathworks.com/help/matlab/ref/flip.html
Signed BDA
2 Comments
Steven Lord
on 19 Oct 2016
Lots of people ask for this because it's a fairly easy homework assignment and so it is one that's often assigned in courses where students are being introduced to MATLAB.
Bhuvana Krishnaraj
on 9 Jan 2020
Edited: Walter Roberson
on 10 Jan 2024
x=input('Enter number: ');
temp=x;
y = 0;
while x > 0
t = mod(x,10);
y = 10*y+t;
x = (x-t)/10; %% without this it will give floating value
end
if(y==temp)
disp('The number is palindrome');
else
disp('The number is not palindrome');
end
1 Comment
Walter Roberson
on 26 Sep 2020
Suppose the user enters 050. That would certainly appear to be a palindrome. You use input() with no 's' to read it so you get a binary double precision value equal to decimal 50. You proceed to process it numerically and get 10*0 + 5 = 5. But 5 is not 50 so you say No it is not a palindrome. When it should probably be one.
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