Set initial value in Matlab Function block

How can I set the initial value for UP? UPI is my initial value input to the block. How can I make sure UP will accepts thhs value only once (start of the simulation)? Thanks
funciton UP=[UPI]
*UP=UPI;
%#close safety_relieve_valve
SRV=0;
if (UP>UL)
Val=0;
UP=RD;
else
Val=1;
UP=RU;
end
if (UP<LL) & (Val==0)
UP=RD+0.1;
disp(UP);
Val=1;
elseif (UP>=LL) & (Val==1)
UP=UP+0.1;
end*

5 Comments

The issue of the if statement is resolved. Is there any block to extract a single element from the vector (entered from "From Workspace" block) to set as the input to the ML Fctn block?
What do you mean? the same single element each iteration, or the first, then the second, and so on ?
I am required to enter input interactively so I used the "From Workspace" block. This block can only input with vector instead of scalar value. I would like to extract a single element from this vector then.
have you tried Ports and Data Manager?
The input is set as Inherit: same as Simulink. I kept getting error "Expecting scalr...." I changed the type to "double" but no avail.

Sign in to comment.

Answers (2)

You can use persistent declaration
function UP=fcn(UPI)
persistent UPI1
if isempty(UPI1)
UP=UPI
else
UP=UPI1
end
%your code
UPI1=UP;

11 Comments

What is UP1 & UPI1?
Thanks.
UP1 does not exist (The answer was edited) UPI1 is an intermediate variable
Referring to my code above, my if (UP>UL) is not executed. I checked the value of UP & it is greater than UL during the simulation. Any suggestion?
Thanks.
What UL and other variables represent? If they are constants from workspace, use Ports and Data Manager
UL, LL & UPI are all constants. I tried different opitons with Port and Data manager but the "if (UP>UL) is still not executed. BTW, does size matter (it is currently set at -1)? Thanks.
What is the size of UL?
UL equals to 18 & its sapling size is inf.
its sapling size is inf ? what is that ?
I meant sampling time in the property box of constant block.
Instead of using the 'elseif' statement, I created another 'if' statement & it worked. But there are some other issues I would like to resolve. I will post it later. Thanks again.
function UP = UPC(t,LL,u1,u2,u3,u4,u5,u6,u7,u8)
%#codegen
persistent LLI
if isempty(LLI)
UP=LL;
else
UP=LLI;
end
My code
LLI=UP;
Azzi, I kept getting the error message "LLI is not defined..." when I attempted to run the simulation. "LL" is my IC for UP. Any idea? Thanks.

Sign in to comment.

Hi
I have a similar problem, could you find a real solution.
Best regards?

Categories

Asked:

on 17 Apr 2014

Answered:

on 4 Dec 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!