how to draw a trajectory
14 views (last 30 days)
Show older comments
Hi
i have a differential equation like this:
x'' + x + x^2 = 0
its a chaos problem and i want to display the trajectories.it has two fix point, a saddle at (-1,0) and a repellor at (0,0).
we can transform the equation to ODE by this:
x'= y
y'= -x -x^2
Accepted Answer
Mischa Kim
on 22 Apr 2014
Mostafa, try something like
function my_phase()
IC = rand(10,2);
hold on
for ii = 1:length(IC(:,1))
[~,X] = ode45(@EOM,[0 2],IC(ii,:));
x = X(:,1);
y = X(:,2);
plot(x,y,'r')
end
xlabel('x')
ylabel('y')
grid
end
function dZ = EOM(t, z)
dZ = zeros(2,1);
x = z(1);
y = z(2);
dZ = [ y;...
- x - x^2];
end
You can use the IC vector to place the initial conditions to specifically show the dynamics around the fixed points.
3 Comments
Mischa Kim
on 22 Apr 2014
As I pointed, use the IC vector, e.g.,
IC = bsxfun(@plus, [-1 0], rand(100,2)-0.5*ones(100,2));
You probably need to zoom to display the interesting part of the plot.
More Answers (0)
See Also
Categories
Find more on Ordinary Differential Equations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!