# Scatter plot does not display point 0,0 when double precision

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chris on 23 Apr 2014
Commented: AJ von Alt on 23 Apr 2014
I have the following code which works as intended, plotting 3 points.
x = [0 0; 12 0; 6 6];
scatter(x(:,1), x(:,2), 100, 'fill');
However, when I interject the following line
x = 1.01 * x;
which effectively turns everything into double precision, then the point 0,0 does not display
why is that, and how can I make it so that it also displays?

José-Luis on 23 Apr 2014
Trying to understand the mess that is Matlab's graphics engine is a real pain. I can only recommend a workaround:
x = [0 0; 12 0; 6 6];
figure(1)
scatter(x(:,1), x(:,2), 100, 'fill');
x = 1.01 * x;
figure(2)
scatter(x(:,1), x(:,2), 100, 'fill'); %Now readjust the axes so you can see what you actually plotted:
set(gca,'XLim',x([1 2],1)); %you can use min() max() in order to avoid hard coding the indices.
set(gca,'YLim',x([1 3],2));

AJ von Alt on 23 Apr 2014
This looks like an issue with the Painters renderer. Switching to OpenGL resolves the issue on my end.
x = [0 0; 12 0; 6 6];
figure('renderer','OpenGL')
scatter(x(:,1), x(:,2), 100, 'fill');
y = 1.01 * x;
figure('renderer','OpenGL')
scatter(y(:,1), y(:,2), 100, 'fill');
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AJ von Alt on 23 Apr 2014
The renderer is used to draw the plot in the figure. It is defined independently for each figure so you will need to specify it every time you create one.
You can change the renderer of the current figure to "OpenGL" using the command:
set( gcf , 'renderer' , 'OpenGL' )

chris on 23 Apr 2014

chris on 23 Apr 2014
This works! It is weird though why the original version doesn't behave seamlessly.
Anyways, thanks everybody for the help.