How could I solve this error?
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this code does not have any problem with respect to r and t, but when I add interval for t and r it gives this error
thanks for helping
B=(2/pi)^(1/2);
r1=0.00001;
k=0.42;
Cp=3600;
g=1000;
rho=1048;
Tb=37;
qm=300;
w=0.0005;
ra=0.01;
%%
c=w*rho*Cp;
r_distance=ra*2;
time_total=1;
dr=r_distance/10;
dt=0.1;
rmesh=0:dr:r_distance;
tmesh=0:dt:time_total;
rskip=2;
tskip=2;
number_iterations=2;
nr=length(rmesh);
nt=length(tmesh);
V=zeros(nt,nr);
for i=1:nt
for j=1:nt
for m=1:number_iterations
q = int((((B*(rp*sqrt(c))^(-0.5)*sin(rp*sqrt(c))/(sqrt(rp)*B*(sqrt(c))^(-0.5)*sin(sqrt(c)))))-1)*rp*sin(m*pi*rp),rp,0,1); % the integral r prime from 0 to 1
first_term = symsum((exp((m*pi)^2+c)*(-tmesh(j)))*sin(m*pi*rmesh(i))*q, m, 1, 10); % a summation
end
end
end
Error using sym/symsum (line 52)
Cannot compute the sum with respect to '1'. The summation index must be a symbolic variable.
Error in test (line 36)
first_term = symsum((exp((m*pi)^2+c)*(-tmesh(j)))*sin(m*pi*rmesh(i))*q, m, 1, 10); % a summation
7 Comments
darova
on 20 Aug 2021
You don't have any symbolic variables. Why don't just use sum?
Bajdar Nouredine
on 20 Aug 2021
darova
on 20 Aug 2021
You have to declare m as symbolic variable
syms m
Bajdar Nouredine
on 20 Aug 2021
darova
on 20 Aug 2021
Here is the problem: oyu are using the same variable

Bajdar Nouredine
on 20 Aug 2021
darova
on 21 Aug 2021

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