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I have 45x484 matrix but when I calculate coeff pca function, I am getting coeff with 484x44 matrix which causes errors in biplot. Why is the rows and columns switch places?

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ack
ack on 31 Aug 2021
Commented: ack on 4 Sep 2021
%from struct to matrix using function
T1 = createDataMatrix(REC);
x=ismissing(T1);
y=any(x,1);
z=T1(:,~y);
a=z;
% scaling data for each column using standardised Z
ZM=zscore(a);
ZM=ZM-mean(ZM);
%PCA using Matlab built-in function
[coeff,score,latent,~,explained,~]=pca(ZM);

Accepted Answer

Ive J
Ive J on 31 Aug 2021
Well you should find the answer in your problem not MATLAB pca function. You have 45 observations with 484 variables, so degree of freedom (you already centered your variables) in your case would be 44 and that's the max number of PCs with a non zero variance. You need to look at the total variance explained and pick those PCs explaining much of the variance (let's say 90%); I highly doubt the number of PCs explaining that much of variance even exceeds half of variables in a real case situation (though I admit depends on the nature of the problem).
Bottom line: pca function works just fine.
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