# how do you sum using loop?

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### Answers (1)

Wan Ji
on 31 Aug 2021

Edited: Wan Ji
on 1 Sep 2021

x=1:100;

f=@(x)x.*(1+x);

S=sum(f(x));%this should be ok

%or use loop

f=@(x)x.*(1+x);

S=0;

for i=1:100

S=S+f(i);

end

disp(S)

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##### 1 Comment

John D'Errico
on 1 Sep 2021

x=1:100;

f=@(x)x.*(1+x)

S=sum(f(x));%this should be ok

S

So f is a function handle. It is vectorized, so that when you pass in a vector of length 100, f(x) returns a vector of elements, of length 100. Now sum sums the vector, so your first solution will work.

But now look at the code you wrote in the loop. In there, you treat f as a VECTOR, forgetting that f is a function handle, NOT itself a vector.

The other thing I would do is to change the loop. That is, rather than hard coding the number of terms in the loop, do this:

x=1:100;

f=@(x)x.*(1+x);

S=0;

for i=1:numel(x)

S=S+f(x(i));

end

disp(S)

You should see that I made two changes. I set the length of the loop to be the length of x. Hard coding the length of a loop there is asking for a bug to happen, when tomorrow arrives and you change the length of x. Now the loop is either too long or too short. In either case, you create a bug.

More important of course, was the change in this line to read:

S=S+f(x(i));

Again, f is a function handle. You cannot index into a function handle.

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