my code keep running continuously with no stop ... help appreciate

Hi all,
I have my code here i tried sevral time with many suggetuon between break and while loop but keep running with no stop.
I need to test all element in nodes lalel to meet the conditions and then if the node label set meet the condition stop and give me answer(it sould test all the for loop). node label is the random perm.
this my matlab version (MATLAB : Version 9.10 (R2021a))
code:
nodeslabel=[0,randperm(4)]
for i=1:n
for j=1:n
if i~=j
if % condition met (print)
else
% exist the all if condition and for for loops and make
% new nodeslabel=[0,randperm(4)] till if conditon met
end
end
end
end

1 Comment

This code:
nodeslabel=[0,randperm(4)]
for i=1:n
for j=1:n
if i~=j
if % condition met (print)
else
% exist the all if condition and for for loops and make
% new nodeslabel=[0,randperm(4)] till if conditon met
end
end
end
end
does not have a while loop and will not be an infinite loop unless n is infinite. Either post the actual code with a while loop in it, or step through it with the debugger. Evidently you're not debugging your code by stepping through it line by line and I'm wondering why not.

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Answers (1)

In your code, [while ... loop] has to be eliminated and then everything else works ok.
% while true % To be eliminated
...
% end

3 Comments

if I eliminate while loop it gives me nodeslabel [] that does not meet the if condition . my idea is (if the if condition deos not meet , i need to get out of the for loop and make a new randperm set for nodes label untill met the conditions .
then there must be the condition to set while operator to halt, e.g.:
Halt = 1;
while Halt == 1
...
% Condition is met
Halt = 0;
end
I've tried that unfortunatly doesn't do the process again and give me the sol when the condition met.
I really want same this idea after else and if ...
nodeslabel=[0,randperm(4)]
for i=1:n
for j=1:n
if i~=j
if % condition met (print)
else
% exist the all if condition and for for loops and make
% new nodeslabel=[0,randperm(4)] till if conditon met
end
end
end
end

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Asked:

on 25 Sep 2021

Commented:

on 25 Sep 2021

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