Is the following program correct

s=0;
n=input("no of terms");
x=input("put the value of x");
for i=0:n-1
    s=(-1).^i*(x.^i)/(factorial(x));
end
disp(s)

;

[Stephen23]

@Deepak Singh: your code does not add to s, instead your code just returns the result of the last division.

You need to have something like s = s + ...

Answer 1

[Voss]

s=0;
n=input("no of terms");
x=input("put the value of x");
for i=0:2:2*(n-1)
    s=s+(-1).^(i/2)*(x.^i)/(factorial(i));
end
disp(s)

Answer 2

[Torsten]

To avoid overflow in the x^i and factorial(i) terms, it is advisable to code it this way:

n = input("no of terms");
x = input("put the value of x");
summand = 1.0;
summe = 1.0;
for i = 1:n-1
    summand = -summand * x/(2*i-1) * x/(2*i);
    summe = summe + summand
end