solve the equation for a large frequency range

I want to solve the below equation for the frequency range of 1Khz to 100MHz.

the equation is factor=Rsh/(Rsh+j*2*pi*frequency*Lsh)

here,

 Rsh=0.01*pi

and

Lsh=5*10^-9

. But when I run the code it shows matrix mismatch

freq=1e+3:1e+8;%frequency range
Rsh=0.01*pi;
d=Rsh+(2*pi*freq*i*5*10^-9);

factor=Rsh/d;

Answer 1

[Walter Roberson]

 Rsh=0.01*pi

Rsh = 0.0314

Lsh=5*10^-9

Lsh = 5.0000e-09

freq=1e+3:1e+8;%frequency range
Rsh=0.01*pi;
d=Rsh+(2*pi*freq*i*5*10^-9);
factor = Rsh ./ d;

In MATLAB, the / operator is "matrix right divide". Rsh/d is roughly equivalent to Rsh * pinv(d) but with some restrictions about the sizes; the * indicated here is algebraic matrix multiplication, "inner product".

What you wanted was element-by-element division, which in MATLAB is the ./ operator.

[Tasin Nusrat]

if I later multiply each value for factor, how should I do that?

suppose

b=factor.*2*pi*freq*i*3.5e-12;

I am not sure if it's the correct format to use the values of factor

[Walter Roberson]

Rsh=0.01*pi
Lsh=5*10^-9
freq=1e+3:1e+8;%frequency range
Rsh=0.01*pi;
d=Rsh+(2*pi*freq*i*5*10^-9);
factor = Rsh ./ d;

b = 2 .* pi .* 3.5e-12 .* i .* factor .* freq;

Note: if i is intended to represent the imaginary constant, then

b = 3.5e-12i .* 2 .* pi .* factor .* freq;

[Tasin Nusrat]

Thanks a lot