explanation for syntax of arrayfun
26 views (last 30 days)
Show older comments
Hello
can anyone explain the syntax of the following code pls...
B= arrayfun(@(x) x, A, 'uni', 0);
thanks in advance
0 Comments
Accepted Answer
Geoff Hayes
on 24 Aug 2014
Abirami - see the documentation at arrayfun for details on the usage of this function. From your example,
B = arrayfun(@(x) x, A, 'uni', 0);
arrayfun will apply the anonymous function @(x) x on each element of A. The uni string must be equivalent to UniformOutput being set to 0 (or false) which from the documentation states Requests that the arrayfun function combine the outputs into cell arrays B1,...,Bm. The outputs of function func can be of any size or type. So here, func is the anonymous function.
Suppose
A = [1:5]'
A =
1
2
3
4
5
then
B = arrayfun(@(x) x, A, 'uni', 0)
B =
[1]
[2]
[3]
[4]
[5]
The output B is a 5x1 cell array. B is identical to A since our anonymous function would take in an element (x) and then just return it. If we had
B = arrayfun(@(x) 2*x, A, 'uni', 0)
B =
[ 2]
[ 4]
[ 6]
[ 8]
[10]
So each element in B is double that of A. Note that if we removed the uni option (and its value)
B = arrayfun(@(x) 2*x, A)
B =
2
4
6
8
10
Then B is no longer a cell array.
More Answers (0)
See Also
Categories
Find more on Structures in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!