to perform iris normalisation

Answers (2)

omar mohamed
omar mohamed on 10 Dec 2012
Edited: Walter Roberson on 29 Jun 2017
function imP = ImToPolar (imR, rMin, rMax, M, N)
% IMTOPOLAR converts rectangular image to polar form. The output image is
% an MxN image with M points along the r axis and N points along the theta
% axis. The origin of the image is assumed to be at the center of the given
% image. The image is assumed to be grayscale.
% Bilinear interpolation is used to interpolate between points not exactly
% in the image.
%
% rMin and rMax should be between 0 and 1 and rMin < rMax. r = 0 is the
% center of the image and r = 1 is half the width or height of the image.
%
% V0.1 7 Dec 2007 (Created), Prakash Manandhar pmanandhar@umassd.edu
[Mr Nr] = size(imR); % size of rectangular image
Om = (Mr+1)/2; % co-ordinates of the center of the image
On = (Nr+1)/2;
sx = (Mr-1)/2; % scale factors
sy = (Nr-1)/2;
imP = zeros(M, N);
delR = (rMax - rMin)/(M-1);
delT = 2*pi/N;
% loop in radius and
for ri = 1:M
for ti = 1:N
r = rMin + (ri - 1)*delR;
t = (ti - 1)*delT;
x = r*cos(t);
y = r*sin(t);
xR = x*sx + Om;
yR = y*sy + On;
imP (ri, ti) = interpolate (imR, xR, yR);
end
end
function v = interpolate (imR, xR, yR)
xf = floor(xR);
xc = ceil(xR);
yf = floor(yR);
yc = ceil(yR);
if xf == xc & yc == yf
v = imR (xc, yc);
elseif xf == xc
v = imR (xf, yf) + (yR - yf)*(imR (xf, yc) - imR (xf, yf));
elseif yf == yc
v = imR (xf, yf) + (xR - xf)*(imR (xc, yf) - imR (xf, yf));
else
A = [ xf yf xf*yf 1
xf yc xf*yc 1
xc yf xc*yf 1
xc yc xc*yc 1 ];
r = [ imR(xf, yf)
imR(xf, yc)
imR(xc, yf)
imR(xc, yc) ];
a = A\double(r);
w = [xR yR xR*yR 1];
v = w*a;
end
end

3 Comments

Sir can you please tell us what should be the value of Mr and Nr??
Mr and Nr will be assigned the size of the input image iMR.
Note: iMR should be 2D (grayscale) not RGB.
Thank you very much sir!!

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