how can remove the object that has the maximum distance from center of image?
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if we have some objects in a binary image how can remove the object that has the maximum distance from center of image? for example if this is my image:
how can I obtain this image as result:
thanks
4 Comments
Guillaume
on 17 Oct 2014
By define, I meant tell us what you mean. Is the distance of the object to the centre
- the distance from the object centroid to the centre?
- the distance from the furthest point of the object to the centre?
- the distance from the closest point of the object to the centre?
- something else?
Answers (6)
Matt J
on 17 Oct 2014
Edited: Matt J
on 17 Oct 2014
how can I obtain this image as result:
I don't recommend that you use distance as a criterion. It would work, but for the object you've shown, it seems quicker and easier to use solidity,
S=regionprops(Image,'Solidity','PixelIdxList');
[~,idx]=min([S.Solidity]);
Image(S(idx).PixelIdxList)=0;
This is also shift-invariant, whereas the distance criterion is not.
9 Comments
Matt J
on 17 Oct 2014
Edited: Matt J
on 17 Oct 2014
Using distance as the criterion,
L=bwlabel(Image);
[M,N]=size(Image);
[X,Y]=ndgrid((1:M)-M/2-.5,(1:N)-N/2-.5);
distmask=(X.^2+Y.^2).*Image;
idx=L>0;
Lmin=accumarray(L(idx),distmask(idx),[],@min);
[~,idx]=max(Lmin);
Image(L==idx)=0;
4 Comments
Matt J
on 17 Oct 2014
The error message would have given you the line number of the error. You should be able to use whos() or the workspace browser to inspect the variables used in that line and see which are integers, which are doubles, etc...
Image Analyst
on 17 Oct 2014
sara: Try the attached code (below the image in blue). I basically threshold, do a morphological opening to break away the thin table line, then extract the biggest blob. A snippet:
% Get the binaryImage
binaryImage = grayImage > 135;
% Erode to break away the table from the body
binaryImage = imopen(binaryImage, [1;1;1]);
biggestBlob = ExtractNLargestBlobs(binaryImage, numberToExtract);
It gives the image below:
0 Comments
Image Analyst
on 22 Jan 2015
"Close" has several definitions. See Hausdorf distance. But let's just assume you want the pair that has the lowest distance between the centroids. Just get the centroids using regionprops() into two arrays centroidx and centroidy. Then calculate the distances, something like
distances = zeros(numberOfBlobs, numberOfBlobs);
for b1 = 1 : numberOfBlobs
for b2 = b1 : numberOfBlobs
distances(b1,b2) = sqrt((centroidx(b1)-centroidx(b2))^2+(centroidy(b1)-centroid(b2))^2);
end
end
Then find the min pair
[blob1, blob2] = find(distances == min(distances(:)));
Then use ismember() to extract those two blobs:
binaryImage = ismember(labeledImage, [blob1, blob2]) > 0;
or something like that. That's just off the top of my head and may need editing.
If this answers your question, can you "Accept" my answer?
3 Comments
rsnandi
on 12 Jul 2019
'hi image analyst..... 'how can I calculate the distance of each entroid from upper border line of image so that I can remove the nearest objects(centroids)) from the above image. thanks
Image Analyst
on 13 Jul 2019
Get the bounding box
props = regionprops(binaryImage, 'BoundingBox');
allBB = vertcat(props.BoundingBox);
% Find just top lines alone.
topLines = allBB(:, 2); % Extract column 2.
% Find out which ones are farther away than some threshold.
keepers = topLines > someLineNumber; % Whatever you want, for example 40.
% Extract out those into a new binary image.
newBinaryImage = ismember(binaryImage, find(keepers));
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