State space system gives different bode plot then transfer function matrix
    10 views (last 30 days)
  
       Show older comments
    
I have a discrete-time system with matrices A,B,C and D
I can either create a [state space system][1], sys1 = ss(A,B,C,D,Ts), of it or compute the [transfer function matrix][2], sys2 = C*inv(z*I- A)*B + D
However when I draw the bode plot of both systems, they are different while they should be the same.
What is going wrong here? Does anyone have a clue? I know btw that the bodeplot generated by sys1 and sys3 is correct.
Note that: my system is already discrete and no discritization is either being done by using
    sys1 = ss(A,B,C,D,Ts);
or either
    sys2 = C*inv(z*eye(3) - A)*B + D;
or either
    [num,den] = ss2tf(A,B,C,D);
    sys3 = tf(num,den,Ts);
The script
clear all;
close all;
clc;
Ts = 0.01;
z = tf('z',Ts);
% Discrete system
A = [0 1 0; 0 0 1; 0.41 -1.21 1.8];
B = [0; 0; 0.01];
C = [7 -73 170];
D = 1;
% Set as state space
sys1 = ss(A,B,C,D,Ts);
% Compute transfer function
sys2 = C*inv(z*eye(3) - A)*B + D;
% Compute the actual transfer function
[num,den] = ss2tf(A,B,C,D);
sys3 = tf(num,den,Ts);
% Show bode
bode(sys1,'b',sys2,'r--',sys3,'g--');
[1]: http://en.wikibooks.org/wiki/Control_Systems/MIMO_Systems#State-Space_Representation
[2]: http://en.wikibooks.org/wiki/Control_Systems/MIMO_Systems#Transfer_Function_Matrix
0 Comments
Accepted Answer
  Sandip Kumar
    
 on 29 Oct 2014
        The sys2 created is not the minimal realization of the system, and if you perform minimal realization you will get back the same system:
>> minreal(sys2)
ans =
z^3 - 0.1 z^2 + 0.48 z - 0.34
-----------------------------
z^3 - 1.8 z^2 + 1.21 z - 0.41
Sample time: 0.01 seconds
Discrete-time transfer function.
which is the same as the sys3
>> sys3
sys3 =
z^3 - 0.1 z^2 + 0.48 z - 0.34
-----------------------------
z^3 - 1.8 z^2 + 1.21 z - 0.41
Sample time: 0.01 seconds
Discrete-time transfer function.
There are recommended working with model conversions: http://www.mathworks.com/help/control/ug/conversion-between-model-types.html#f3-1039600
And I understand this is what you are witnessing:
In addition, converting back and forth between model types can introduce additional states or orders, or introduce numeric inaccuracies. For example, conversions to state space are not uniquely defined, and are not guaranteed to produce a minimal realization for MIMO models.
Thanks, Sandip
0 Comments
More Answers (0)
See Also
Categories
				Find more on Time and Frequency Domain Analysis in Help Center and File Exchange
			
	Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
