How to calculate array factor in matlab

I m trying to write matlab code for this expression.
Can anyone help me with this?
Thanks!!!!

11 Comments

What have you tried so far? This doesn't look like it should be too complicated to write.
Note that the subscripts are very hard to read in your image.
I have tried this: Here there are two rings 1st ring 4ele and 2nd ring ring 16ele. subscripts for first summation:m=1:M (here M=1,2) subscripts for second summation:Nm (here Nm=4,16) i.e when m=1 Nm=4 and when m=2 Nm=16.
I hope you undersood this .
I am not getting the result. help me @Rik
AF(1,1)= 0;n=[4 16]; %no of ele
phi1=[90:90:360 zeros(1,12); 22.5:22.5:360]
l=[1 4] %mode
r=[0.5 2.5]*lambda %radii of each ring
k=(2*pi)/(lambda);
phio=0;
phi=0;
theta=0;
for m=1:2
for i=1:n(m)
AF= AF + (exp((1j).*(((k)*(r(m))*(sin(deg2rad(theta)))*(cos((deg2rad(phi))-(deg2rad(phi1(m,i))))) + ((l(m))*((-k)*r(m)*cos((deg2rad(phio))-(deg2rad(phi1(m,i))))))))));
end
AFk=abs(AF);
end
I am getting the output @Rik. as 9.741 .
I want to know this program is right?As I am not getting required output which should be zero.
I can't properly read you function, so I can't absolutely confirm you did it correctly.
The main advice I have for you is to split your calculation into several parts you can more easily read. One main thing would be to move the calls to deg2rad outside the loop.
If you post a clearer version of your mathematical notation I can try to help you check if this is correct.
Can you see this @Rik
Yes, this I can read.
I would convert this to Matlab as follows:
lambda=__;
M=2;
N=[4 16];
K=(2*pi)/lambda;
r=[0.5 2.5]*lambda;
theta=0;
phi=[90:90:360 zeros(1,12); ...
22.5:22.5:360];
phi_=0;
alpha=__;
s=0;
for m=1:M
for n=1:N(m)
tmp=K * r(m) * sin(theta) * cos(phi_-phi(m,n)) + alpha(m,n);
s=s + W(m) * exp(1j*tmp);
end
end
alpha(m,n)=-k*r(m)*cos(phi0-phi(m,n)) @Rik
intializing s as?
M=2
for m=1:M
for n=1:n(m)
tmp=(k * r(m) * sin(theta) * cos(phio-phi(m,n))) - (k * r(m) * cos(phio-phi(m,n)));
s=s + W(m) * exp(1j*tmp);
end
end
@rik
tq it was bit helpful @Rik
You could also calculate alpha in your loop:
s=0;
for m=1:M
for n=1:N(m)
alpha=-K*r(m)*cos(phi0-phi(m,n));
tmp=K * r(m) * sin(theta) * cos(phi0-phi(m,n)) + alpha;
s=s + W(m) * exp(1j*tmp);
end
end

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Asked:

on 23 Dec 2021

Edited:

on 24 Dec 2021

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