Timeit on pause(2) returns weird ouput
3 views (last 30 days)
Show older comments
I am trying to get the timeit function to work.I read https://uk.mathworks.com/help/matlab/ref/timeit.html and get the example:
X = rand(100);
f = @() svd(X);
t1 = timeit(f)
I want to try this using the pause(2), since this should take about 2 seconds:
g = @() pause(2);
t2 = timeit(g)
the output is
t2 =
3.4639e-06
which is a lot less than the expected 2 seconds. Clearly I am missunderstanding something (which probably makes my more serious attempts at using timeit also wrong), but what?
0 Comments
Answers (1)
Peter Perkins
on 2 Mar 2022
The issue is pause, not timeit:
"STATE = pause(...) returns the state of pause previous to processing the input arguments."
>> t2 = timeit(g,0)
t2 =
2.000208413333
0 Comments
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!