
How do i get a direction field plot?
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Hello, I need to plot a direction field for this differential equation
dP/dt=0.0015*P*(1-(P/6000))
how would I do it?
Thank you for helping.
0 Comments
Accepted Answer
Sam Chak
on 20 Apr 2022
Edited: Sam Chak
on 20 Apr 2022
Hi @Tuân Nguyen
Because there are two equilibrium points
and
, I think it should look like this.
[T, P] = meshgrid(0:6e3/14:6e3, 0:6e3/14:6e3);
S = 0.0015*P.*(1 - (P/6000));
L = sqrt(1 + S.^2);
U = 1./L;
V = S./L;
quiver(T, P, U, V, 0.5)
axis square
xlabel('t')
ylabel('P(t)')

3 Comments
Sam Chak
on 20 Apr 2022
Hi @Tuân Nguyen
In this line, you can change the range of P.
[T, P] = meshgrid(0:(6000-0)/14:6000, 0:(8000-0)/14:8000);
Here is the syntax:
x_start:h:x_end
where h is the spacing between the points.
(8000-0)/14
will generate 15 points between 0 to 8000 in P
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