Using BVP solver to solve 4th order non-linear ODE
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Hi, I am trying to solve an ODE of the following structure
-K1 y''''+K2(y) y''+ A(y) y'^2=0 with the boundary conditions y(0)=y(5)=0, y'(0)=y'(5)=0.1
This is a highly nonlinear ODE with fourth order gradients. I tried to structure it in the way that is required as an input to bvp4c, defining y'(1)=y(2); y'(2)=y(3); y'(3)=y(4); y'(4)= (K2(y(1))*y(2)+A(y(1))*y(1)^2)
and the boundary conditions as y1(0); y1(5); y2(0)-0.1; y2(5)-0.1
But this is not working since apparently y(3) is not accepted by bvp4c.
Please let me know how to go about it and if there is another way to solve this in Matlab using inbuilt routines.
Thank you
Answers (1)
Torsten
on 23 Jan 2015
0 votes
According to your differential equation,
y4'=(K2(y1)*y3+A(y1)*(y2)^2)/K1;
Best wishes
Torsten.
6 Comments
Pragya Srivastava
on 23 Jan 2015
Torsten
on 26 Jan 2015
From the error message you supply, I would conclude that you only supply a vector with two components as initial condition for y.
Could you include the call to bvp4c to check this ?
Best wishes
Torsten.
Pragya Srivastava
on 29 Jan 2015
Torsten
on 30 Jan 2015
must read
function res=fourbc(ya,yb)
res=[ya(1);yb(1); ya(2)-0.1;yb(2)-0.1];
end
Best wishes
Torsten.
Pragya Srivastava
on 30 Jan 2015
Torsten
on 2 Feb 2015
In the MATLAB examples, the vector of initial conditions is a row vector, so
solinit=bvpinit(linspace(0,5,20),[0 0 0 0])
should be correct.
I don't know what you return in ODEFUN, but it must be a column vector of length 4.
Best wishes
Torsten.
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