How to find x value for certain y value of a lineplot in matlab

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Edited: Sam Chak on 8 Jun 2022
I want to get EV value at P=50% without real data point at P=0.5 in the lineplot.

EV=[-15 -14 -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15]
P=[0.0312500000000000,0,0.0312500000000000,0.0156250000000000,0.00625000000000000,0.0208333333333333,0.0186011904761905,0.0429687500000000,0.0282118055555556,0.0312500000000000,0.0539772727272727,0.0758838383838384,0.130080856643357,0.158545100732601,0.256227106227106,0.439955357142857,0.648752289377290,0.705156822344322,0.740785256410257,0.809659090909091,0.869444444444444,0.903125000000000,0.912946428571429,0.949218750000000,0.971726190476191,0.989583333333333,0.987500000000000,0.992187500000000,0.968750000000000,1,1]

Torsten on 8 Jun 2022
EV = EV(5:14);
P = P(5:14);
EV_05 = interp1(P,EV,0.5)

Before posting online, I tried to fit a linear equation according to the nearest two data points. But I didn't get what I want proprely. May be chose a larger interval will be better fit my data.Thanks for your good explanation!

SALAH ALRABEEI on 8 Jun 2022
You can find the the EV from the index of p value.
Example;
a=[4,2,3,5,6,7]
a = 1×6
4 2 3 5 6 7
b = a.^2
b = 1×6
16 4 9 25 36 49
Now, to find what is a at b= 9!
inx = find(b==9);
a(inx)
ans = 3
Sam Chak on 8 Jun 2022
If the specific data and governing equation are unavailable, then you can only rely on Interpolation and Approximation Theory to find out the value.
More importantly, can you furnish the 17 visible data points (EV, P) for one-step further investigation of your NaN result?

Sam Chak on 8 Jun 2022
No joke, but this is the graphical approach.
Sam Chak on 8 Jun 2022
Edited: Sam Chak on 8 Jun 2022
Cute? Vote if you think it is cute, but I guess you are probably cuter, Ms. Zhou 😊