why do I get the wrong angle
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why do i keep getting a negatie value for angle
Answers (1)
David Hill
on 14 Jun 2022
Edited: David Hill
on 14 Jun 2022
mo=2.5;
y=1.4;
angle=10;
fun=@(a)((2*(1+((y-1)/2)*mo^2*(sind(a)).^2))./(((y+1)*mo^2*sind(a).*cosd(a))))-tand(a-angle);
A=fzero(fun,32);
3 Comments
David Hill
on 14 Jun 2022
You could also plot and see that there are two solutions between (0 - 90).
mo=2.5;
y=1.4;
angle=10;
fun=@(a)((2*(1+((y-1)/2)*mo^2*(sind(a)).^2))./(((y+1)*mo^2*sind(a).*cosd(a))))-tand(a-angle);
x=3:.1:87;
plot(x,fun(x));
David Hill
on 14 Jun 2022
Edited: David Hill
on 14 Jun 2022
When you graph the function you see solutions should be around 30 and 80. fzero requires an initial guess. 32 is not an exact solution.
mo=2.5;
y=1.4;
angle=10;
fun=@(a)((2*(1+((y-1)/2)*mo^2*(sind(a)).^2))./(((y+1)*mo^2*sind(a).*cosd(a))))-tand(a-angle);
A=fzero(fun,30)
mo=2.5;
y=1.4;
angle=10;
fun=@(a)((2*(1+((y-1)/2)*mo^2*(sind(a)).^2))./(((y+1)*mo^2*sind(a).*cosd(a))))-tand(a-angle);
A=fzero(fun,80)
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