how to solve this

Area A= pi*r^2 where r=pi^1/3-1

[Rik]

Are you posting homework questions?

Answer 1

[Sam Chak]

The Area A computed by MATLAB is as correct as the radius r given by you.

r = pi^1/3-1

r = 0.0472

A = pi*r^2

A = 0.0070

Answer 2

[Voss]

r = pi^1/3-1 % == (pi^1)/3 - 1 == pi/3 - 1

r = 0.0472

A = pi*r^2

A = 0.0070

r = pi^(1/3)-1 % pi to the one-third power, minus one

r = 0.4646

A = pi*r^2

A = 0.6781