How to plot two piecewise functions on same graph?

I need to plot the attached functions on same plot. Please help me to write the Matlab code.
Thanks in advance!

Answers (1)

range = [-2 2];
fplot([f, g] , range)

17 Comments

can you please send me full code?
I have tried but it is not running.
x = linspace(0, 1 );
f = @(x) (x<0.5) .* (30.*x) + (x>=0.5).* (70.*x)-20;
g = @(x) (x<0.5).* 30.*(1-x) + (x>=0.5).* 50-(70.*x) ;
figure
plot(x, [f(x); g(x)], 'linewidth', 1.5 )
grid
axis([min(x) max(x) 0 50 ])
xlabel('x ')
ylabel('Function Value ')
legend('f(x)','g(x)', 'Location','best ')
The above was some other function. Both are not running.
x = linspace(0, 1 );
f = @(x) (x<0.5) .* (7-3.* 'sqrt'(-2.* ('ln'(2.*x)))) + (x>=0.5).*(7+2.* 'sqrt'(-2.* ('ln'(2-2.*x))));
g = @(x) (x<0.5).* (7-5.* 'sqrt'(-1.* ('ln'(2-2.*x)))) + (x>=0.5).*(7+4.* 'sqrt'(-1.* ('ln'(2.*x))));
figure
plot(x, [f(x); g(x)], 'linewidth', 1.5 )
grid
axis([min(x) max(x) 0 1 ])
xlabel('x ')
ylabel('Function Value ')
legend('f(x)','g(x)', 'Location','best ')
Your question defines symbolic formulas, so you need to use the symbolic toolbox or you need to modify the question.
x = linspace(0, 1 ).';
f = @(x) (x<0.5) .* (30.*x) + (x>=0.5).* (70.*x)-20;
g = @(x) (x<0.5).* 30.*(1-x) + (x>=0.5).* 50-(70.*x) ;
figure
plot(x, [f(x), g(x)], 'linewidth', 1.5 )
Can you please search the error in this code?
x = linspace(0, 1 );
f = @(x) (x<0.5) .* (7-3.* 'sqrt'(-2.* ('ln'(2.*x)))) + (x>=0.5).*(7+2.* 'sqrt'(-2.* ('ln'(2-2.*x))));
g = @(x) (x<0.5).* (7-5.* 'sqrt'(-1.* ('ln'(2-2.*x)))) + (x>=0.5).*(7+4.* 'sqrt'(-1.* ('ln'(2.*x))));
figure
plot(x, [f(x); g(x)], 'linewidth', 1.5 )
'ln'(2-2.*x)
if that was valid syntax at all, then it would mean that you want to take the vector of characters ['l' 'n'] and index that vector at the indices calculated by 2-2.*x, getting back a vector of characters.
By the way, matlab uses log() not ln()
@Amna Habib, From where you learned
'sqrt'()
and
'ln'()
In Maple you could in theory use code such as
`sqrt`(x)
Everything inside the back quotes becomes part of an atomic name that can be used as an identifier, and there are ways to code symbols and unicode characters. So you could, for example, create a function named `2π`
Commonly, Maple strips the back quotes out in presentation mode (2d output) and renders the symbols, but there are some cases such as copy and paste in 1d (code) mode where it leaves the back quotes unless the characters involved form a valid identifier.
@Walter Roberson, thanks for the background information. 👍
i have corrected this code but I think there is still an error in function 'g'. can you please mention?
here is the code. the the file showing graphical result is attached.
x = linspace(0, 1 );
f = @(x) (x<0.5) .* (7-3.* sqrt(-2.* (log(2.*x)))) + (x>=0.5).*(7+2.* sqrt(-2.* (log(2-(2.*x)))));
g = @(x) (x<0.5).* (7-5.* sqrt(-1.* (log(2-(2.*x))))) + (x>=0.5).*(7+4.* sqrt(-1.* (log(2.*x))));
figure
plot(x, [f(x); g(x)], 'linewidth', 1.5 )
Warning: Imaginary parts of complex X and/or Y arguments ignored.
x = linspace(0, 1 ).';
f = @(x) (x<0.5) .* (30.*x) + (x>=0.5).* (70.*x)-20 ;
g = @(x) (x<0.5).* 30.*(1-x) + (x>=0.5).* 50-(70.*x ) ;
figure
plot(x, [f(x), g(x)], 'linewidth', 1.5 )
Sorry I have another confusion in this plot too. I didn't found any error but the graph is not correct as compared to the manual plotting. Here is the code and tghe graph file is attached in .png
Thanks in advance!
You should recheck your definition of g, as it is everywhere complex. Consider for example x = 0, then 2-2*x is 2-0, log(2) is positive, -1.*log(2) is negative, sqrt(-log(2)) is complex.
x = linspace(0, 1 );
f = @(x) (x<0.5) .* (7-3.* sqrt(-2.* (log(2.*x)))) + (x>=0.5).*(7+2.* sqrt(-2.* (log(2-(2.*x)))));
g = @(x) (x<0.5).* (7-5.* sqrt(-1.* (log(2-(2.*x))))) + (x>=0.5).*(7+4.* sqrt(-1.* (log(2.*x))));
figure
plot(x, [f(x); g(x)], 'linewidth', 1.5 )
Warning: Imaginary parts of complex X and/or Y arguments ignored.
syms X real
F(X) = piecewise( (X<0.5), (7-3.* sqrt(-2.* (log(2.*X)))), (X>=0.5), (7+2.* sqrt(-2.* (log(2-(2.*X))))), 0)
F(X) = 
G(X) = piecewise( (X<0.5), (7-5.* sqrt(-1.* (log(2-(2.*X))))), (X>=0.5), (7+4.* sqrt(-1.* (log(2.*X)))), 0)
G(X) = 
limit(F, X, 0)
ans = 
limit(F, X, 1)
ans = 
limit(G, X, 0)
ans = 
limit(G, X, 1)
ans = 
x = linspace(0, 1 ).';
f = @(x) (x<0.5) .* (30.*x) + (x>=0.5).* (70.*x)-20 ;
g = @(x) (x<0.5).* 30.*(1-x) + (x>=0.5).* 50-(70.*x ) ;
figure
plot(x, [f(x), g(x)], 'linewidth', 1.5 )
syms X real
F(X) = piecewise((X<0.5), (30.*X), (X>=0.5), (70.*X)-20, 0 )
F(X) = 
G(X) = piecewise((X<0.5), 30.*(1-X), (X>=0.5), 50-(70.*X), 0)
G(X) = 
fplot([F, G], [0 1])
x = linspace(0, 1 ).';
f = @(x) (x<0.5) .* (30.*x) + (x>=0.5).* (70.*x)-20 ;
g = @(x) (x<0.5).* 30.*(1-x) + (x>=0.5).* 50-(70.*x ) ;
figure
plot(x, [f(x), g(x)], 'linewidth', 1.5 )
syms X real
F(X) = piecewise((X<0.5), (30.*X), (X>=0.5), (70.*X)-20, 0 )
F(X) = 
G(X) = piecewise((X<0.5), 30.*(1-X), (X>=0.5), 50-(70.*X), 0)
G(X) = 
fplot([F, G], [0 1])
Thanks a lot @Walter Roberson. I appreciate your effort.
Look more closely at your functions
f = @(x) (x<0.5) .* (30.*x) + (x>=0.5).* (70.*x)-20 ;
g = @(x) (x<0.5).* 30.*(1-x) + (x>=0.5).* 50-(70.*x ) ;
Notice that the -20 in f not being multiplied by any condition. Notice that the -70.*x in g is not being multiplied by any condition.

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Asked:

on 23 Jul 2022

Commented:

on 27 Jul 2022

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