Converting Matrix to base b fails

1 view (last 30 days)
the following code should create a multiplication table to the base b
(now in the form of multTable(7,3:10,2:3:33), i know)
when calling the function like above i get an error thrown at "table(i,ii) = a;"
Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-2.
I dont know why. when using table(i,ii) = 0; the programm runs perfectly.
I always thought that dec2base only returns one value thus making filling the matrix pretty easy.
function y = multTable(b, R, C)
table = (R)' * (C);
w = width(table);
h = height(table);
for i= 1:h
for ii = 1:w
a = dec2base(table(i,ii),b);
disp(a);
disp("**")
table(i,ii) = a;
end
end
y = table;
end

Accepted Answer

the cyclist
the cyclist on 9 Aug 2022
dec2base returns a character array representation that can be multiple characters:
dec2base(7,2) % "convert" decimal 7 to base 2
ans = '111'
  1 Comment
Tom Schneider
Tom Schneider on 9 Aug 2022
thx for the answer ! i used str2num to finally get them into the matrix

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!