I want to create a binary matrix with a variable dimensions

I want to create a binary matrix of dimension k x M where k and M are user defined.(k is the number of rows and M is the number of column). And number of zeros and ones in each row are user defined. Also this binary matrix should be a function.

[James Tursa]

What have you done so far? What specific problems are you having with your code?

[Dyuman Joshi]

Seems like home work/assignment.

Check out

input

zeros

ones

function

[Nir Vaishnav]

for kk=1:lnk

m = input('How many zeroes do you need \n');

n = input('how many ones do you need\n');

lnk=nchoosek(m+n,n);

i=n+m;

if i<=1

disp('size of binary sequence is out of range');

else

%Binary sequence contains m zeros and n ones in any order

x1=zeros(1,m);

x1(randn(i,n))=1

%count down the number of switches in such a Binary sequence x1;

end

end

This is what i have done but it creates only arrays i dont understand how to make it into a matrix. and then convert into a function

Answer 1

[David Hill]

k=10;
M=50;
O=randi(M+1,k)-1;%number of ones per row (number of zeros per row= 50 - O)
for n=1:k
    m=[ones(1,O(n)),zeros(1,M-O(n))];
    Matrix(n,:)=m(randperm(M));
end

[Nir Vaishnav]

if i change the value of k,M then it shows the error that left side matrix dimension is not equal to right side.

[David Hill]

You just need to clear Matrix or set Matrix = [ ] at the beginning.

k=10;
M=50;
Matrix=[];
O=randi(M+1,k)-1;%number of ones per row (number of zeros per row= 50 - O)
for n=1:k
    m=[ones(1,O(n)),zeros(1,M-O(n))];
    Matrix(n,:)=m(randperm(M));
end