Find the position of numbers in array
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Hello everybody, I'm trying to find the position of some values in an array. The values i'm interested in are in a 1x182 vector and I want to find they're position in a 1x1820 vector (practically I'm just looking for a percentile). Can you guess how I can find them?
PS: i did it with a for loop using the find function but i think it is a non-efficient way, there must be an easier and fast way!
Thank a lot in advance,
Marco
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Answers (3)
Walter Roberson
on 30 Sep 2022
percent_present = mean(ismember(SmallVector, LargeVector)) * 100
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Star Strider
on 30 Sep 2022
I am not certain what you are asking.
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Star Strider
on 30 Sep 2022
Getting them is straightforward. Getting them in that exact order requires a bit of coding gymnastics —
a = [4 5 7 2 1 6 3 9 8];
b = [2 7 8];
[~,idx] = ismember(a, b);
[idx_sorted,sortidx] = sort(idx(idx>0));
idx2 = find(idx);
Result = idx2(sortidx)
.
Ergin Sezgin
on 30 Sep 2022
Edited: Ergin Sezgin
on 30 Sep 2022
Hello Marco,
Following code might help with your task:
rng(2022)
inputArray = 100*rand(1,1820); % you should use your array
selectedElems = randperm(1820,182); % random indexing for subset,
yourVector = inputArray(selectedElems); % you should use your vector instead
elemPositions = zeros(size(yourVector)); % result vector for determined positions
for i=1:size(yourVector,2)
elemPositions(1,i) = find(inputArray==yourVector(1,i));
end
isequal(selectedElems, elemPositions) % Compare real and determined positions
Good luck
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