Array Building using Dynamic Field Reference using an Array of Strings

This is an example of what I am trying to do: Data.Field1=[1; 2; 3];

Data.Field2=[4; 5; 6];

Output=Data.({'Field1'; 'Field2'}) - I know this gives an error, but I want to do something similar

Answer (Desired) Output= [1 4; 2 5; 3 6]

I know I can do it using a for loop for field and build the Output. I was wondering if there is a more elegant way to it.

Many thanks in advance

Answer 1

[Jos (10584)]

Something along these lines?

Data.Field1=[1; 2; 3] 
Data.Field2=[4; 5; 6] 
C = struct2cell(Data) 
Output = cat(2,C{:})

[Rajesh Rajaram]

This is awesome!! Thank you. This definitely answers my initial question.

I have a follow up question: What if Data had a lot more fields say Field001...Field100 and I want to collate only some of the fields into an array?

Req_Field = {'Field001'; 'Field010'; 'Field011'..'Field030'}

- this list could change in the future and hence don't want to hard code each field name in my extraction

Thanks again

[Jos (10584)]

Do not set up your data structure like that. Use arrays:

Data.Field(1).values = [1 2 3]
Data.Field(2).values = [4 5 6]

Answer 2

[James Tursa]

>> Data.Field1 = [1;2;3]
Data = 
    Field1: [3x1 double]
>> Data.Field2 = [4;5;6]
Data = 
    Field1: [3x1 double]
    Field2: [3x1 double]
>> Data.Field3 = 1:4
Data = 
    Field1: [3x1 double]
    Field2: [3x1 double]
    Field3: [1 2 3 4]
>> Fields = {'Field1','Field2'}
Fields = 
    'Field1'    'Field2'
>> n = numel(Fields)
n =
     2
>> f = @(y,x)(y.(x))
f = 
    @(y,x)(y.(x))
>> Datas = cell(1,n);
>> Datas(:) = {Data}
Datas = 
    [1x1 struct]    [1x1 struct]
>> cell2mat(cellfun(f,Datas,Fields,'UniformOutput',false))
ans =
     1     4
     2     5
     3     6

[Rajesh Rajaram]

Y'all are awesome!! Many thanks :)