How to solve this equation
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I need to solve the following differntinal equation:
y' = -(1+2n)y
intial condition y(0)=1 , n=1
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Torsten
on 30 Oct 2022
Use pencil and paper.
dy/dt = -(1+2*n)*y
-> dy/y = -(1+2*n)*dt
-> log(y/y0) = -(1+2*n)*(t-t0)
-> y = ?
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