Solving cubic equation with imaginary numbers

5 views (last 30 days)
Hi everyone
I want to solve this equation by multiplying these variables with imaginary numbers and get clear result with s variable and output is in some weird form. What's wrong?
My code below .
clc;
clear;
s1 = 133.9457 + 253.416i
s2 = 133.9457 - 253.416i
s3 = 1339.457
syms s
x = solve(0.00017493*(s-s1)*(s-s2)*(s-s3))
Thanks in advance

Accepted Answer

Stephan
Stephan on 2 Dec 2022
Edited: Stephan on 2 Dec 2022
s1 = 133.9457 + 253.416i;
s2 = 133.9457 - 253.416i;
s3 = 1339.457;
syms s
x_exactly = solve(0.00017493*(s-s1)*(s-s2)*(s-s3))
x_exactly = 
x_numeric = double(x_exactly)
x_numeric =
1.0e+03 * 1.3395 + 0.0000i 0.1339 - 0.2534i 0.1339 + 0.2534i
  3 Comments
Stephan
Stephan on 2 Dec 2022
s1 = 133.9457 + 253.416i;
s2 = 133.9457 - 253.416i;
s3 = 1339.457;
syms s
x_exactly = expand(0.00017493*(s-s1)*(s-s2)*(s-s3))
x_exactly = 
jayvoor
jayvoor on 2 Dec 2022
Thank you very much!! Have a good day sir :)

Sign in to comment.

More Answers (0)

Categories

Find more on Symbolic Math Toolbox in Help Center and File Exchange

Products


Release

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!