How can I set the values of matrix in interval <a, b>?

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Generate a matrix Ru of pseudo-random floating point values from a uniform distribution, a matrix Ri of pseudo- random integer
values from a uniform distribution and a matrix Rn of pseudo-random values from a normal distribution. Let the size of all
matrices be M x N. Let the expected value of Rn be m = 8 and variance v = 3. Let the values of Ru an Ri be from the interval < a,
b > = < 4, 9 >.
Rn = rand( M, N ) ;
Ru = randn( M, N) ;
Ri = randi( [a, b], M, N ) ; % here I know how to set the interval <a, b>
  2 Comments
Stephen23
Stephen23 on 4 Dec 2022
Edited: Stephen23 on 4 Dec 2022
Original question by Ihor retrieved from Google cache:
How can I set the values of matrix in interval <a, b>?
Generate a matrix Ru of pseudo-random floating point values from a uniform distribution, a matrix Ri of pseudo- random integer
values from a uniform distribution and a matrix Rn of pseudo-random values from a normal distribution. Let the size of all
matrices be M x N. Let the expected value of Rn be m = 8 and variance v = 3. Let the values of Ru an Ri be from the interval < a,b > = < 4, 9 >.
Rn = rand( M, N ) ;
Ru = randn( M, N) ;
Ri = randi( [a, b], M, N ) ; % here I know how to set the interval <a, b>
Rik
Rik on 4 Dec 2022
I recovered the removed content from the Google cache (something which anyone can do). Editing away your question is very rude. Someone spent time reading your question, understanding your issue, figuring out the solution, and writing an answer. Now you repay that kindness by ensuring that the next person with a similar question can't benefit from this answer.

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Accepted Answer

DGM
DGM on 4 Dec 2022
Edited: DGM on 4 Dec 2022
Start with:
m = 500;
n = 500;
rrange = [4 9];
mn = 8;
vr = 3;
% uniform distribution with a specified range
Ru = rrange(1) + range(rrange)*rand(m,n);
[min(Ru(:)) max(Ru(:))]
ans = 1×2
4.0000 9.0000
% normal distribution with specified mean, variance
Rn = mn + sqrt(vr)*randn(m,n);
[mean(Rn(:)) var(Rn(:))]
ans = 1×2
7.9939 3.0058
% discrete uniform random integers
Ri = randi(rrange,m,n);
[min(Ri(:)) max(Ri(:))]
ans = 1×2
4 9
  3 Comments
Ihor
Ihor on 4 Dec 2022
Is there tha way in which I can change the range() function because of it in other ToolBox?
DGM
DGM on 4 Dec 2022
oof. I forgot that was in stats toolbox.
Ru = rrange(1) + (rrange(2)-rrange(1))*rand(m,n);

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