How to color the colormap with a set of hexadecimal colors?
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I want to colormap to plot data. I want to use a set of hexadecimal code for the colors of the plot. If I run with following code, I get the plot.
map=[1 0.9 0; 1 0.75 0; 1 0.625 0; 1 0.5 0; 1 0.375 0; 1 0.25 0; 1 0.125 0; 1 0 0];
colormap(map);
But instead I want to use the following set of hexadecimal codes for the plot, for eg.
map = ('#E1F2E3','#CDE5D2','#9CCEA7','#6CBA7D','#40AD5A','#22BB3B','#06592A');
But I run into error stating that
"Error using colormap
Colormap must have 3 columns: [R,G,B]."
How should I solve this issue, please.
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Accepted Answer
Dave B
on 14 Dec 2022
Edited: Dave B
on 14 Dec 2022
Starting in R2020b you can use the validatecolor function to convert hex to rgb (using the 'multiple' option to convert more than one color):
map = {'#E1F2E3','#CDE5D2','#9CCEA7','#6CBA7D','#40AD5A','#22BB3B','#06592A'};
cmap = validatecolor(map, 'multiple')
imagesc(peaks)
colormap(cmap)
colorbar
2 Comments
Stephan
on 14 Dec 2022
For older versions: https://www.mathworks.com/matlabcentral/fileexchange/46289-rgb2hex-and-hex2rgb by @Chad Greene
More Answers (1)
Bora Eryilmaz
on 14 Dec 2022
Edited: Bora Eryilmaz
on 14 Dec 2022
You can use a function like this in a loop:
map = {'E1F2E3','CDE5D2','9CCEA7','6CBA7D','40AD5A','22BB3B','06592A'}
N = numel(map);
newMap = zeros(N,3);
for i = 1:N
newMap(i,:) = hex2rgb(map{i});
end
newMap
function result = hex2rgb(h)
d = hex2dec(h);
r = bitshift(bitand(d, 0xFF0000), -16);
g = bitshift(bitand(d, 0x00FF00), -8);
b = bitshift(bitand(d, 0x0000FF), 0);
result = [r, g, b];
end
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