How to convert decimal to binary without adding leading zeros?

A =[170;149;219;21;0;62;255];
B = dec2bin(A)
'10101010'
'10010101'
'11011011'
'00010101'
'00000000'
'00111110'
'11111111'

I want to remove leading zeros

i.e., the out put should be

10101010

10010101

11011011

10101

0

111110

11111111

I have tried the following

A =[170;149;219;21;0;62;255]

B = dec2bin(A)

B = regexprep( B, '^[0]+', ' ')

But it give the following error

Error using regexprep
The 'STRING' input must be either a char row vector, a cell array of char row vectors, or a
string array.

Answer 1

[Dyuman Joshi]

You will not be able to do that in a char array, due to inconsistent dimensions.

You can, however, obtain the desired result in form of a string array or cell array

A =[170;149;219;21;0;62;255];
y=arrayfun(@(x) string(dec2bin(x)),A)

y = 7×1 string array
    "10101010"
    "10010101"
    "11011011"
    "10101"
    "0"
    "111110"
    "11111111"

z=arrayfun(@(x) dec2bin(x), A, 'uni', 0)

z = 7×1 cell array
    {'10101010'}
    {'10010101'}
    {'11011011'}
    {'10101'   }
    {'0'       }
    {'111110'  }
    {'11111111'}

[Noor Fatima]

Thanks

[Noor Fatima]

@Dyuman Joshi But it takes too much time for large data, Is not there any other way, please

[Dyuman Joshi]

Try this, it should be faster than arrayfun

%preallocation
y=cell(size(A));
for i=1:size(A,1)
    y{i}=dec2bin(A(i));
end

Also, how large is your data?

Answer 2

[Walter Roberson]

A =[170;149;219;21;0;62;255]
B = cellstr(dec2bin(A));
B = regexprep( B, '^0+', '', 'once')

But I wonder if you are looking for character representation or if you are looking for for decimal encoded binary, such as 101 decimal output for decimal 5?

[Dyuman Joshi]

@Walter, the output for 0 is not correct -

A =[170;149;219;21;0;62;255];
B = cellstr(dec2bin(A));
B = regexprep( B, '^0+', '', 'once')

B = 7×1 cell array
    {'10101010'}
    {'10010101'}
    {'11011011'}
    {'10101'   }
    {0×0 char  }
    {'111110'  }
    {'11111111'}

[Noor Fatima]

@Walter Roberson Thank you very much , Yes I am lookong for decimal encoded binary,

[Noor Fatima]

@Walter Roberson Your code works well, but incase of zero I need zero, is it possible?

[Image Analyst]

@Noor Fatima as I'm sure you know, a simple for loop will do it:

A =[170;149;219;21;0;62;255];
B = cellstr(dec2bin(A));
B = regexprep( B, '^0+', '', 'once');
for k = 1 : numel(B)
    if isempty(B{k})
        B{k} = '0';
    end
end
B

B = 7×1 cell array
    {'10101010'}
    {'10010101'}
    {'11011011'}
    {'10101'   }
    {'0'       }
    {'111110'  }
    {'11111111'}

but maybe you're hoping for something more compact and cryptic.