How to make piece-wise function accept single variables and vectors
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I have a piece-wise function that can take a single variable and produce my desired output. However, the problem I am having is when there are vectors instead of single variables. For example, it will not accept vectors (0:1:10) or (1 2 3 4 5), where the code produces no output at all. I have put the x. so that it would do the operations for every variable in a given vector, but it has no effect.
function y = piecewise(x)
if (x>0) & (x<=120) % for 0 < x <= 120
y = ((800*x.^3)-(13.68*(10^6)*x)-(2.5*x.^4)) % Use this equation
elseif (x>120) & (x<=240) % for 120 < x <= 240
y = ((800*x.^3)-(13.68*(10^6)*x)-(2.5*x.^4)+2.5*(x-120)^4) % Use this equation
elseif (x>240) & (x<=360) % for 240 < x <= 360
y = ((800*x.^3)-(13.68*(10^6)*x)-(2.5*x.^4)+2.5*(x-120)^4+600*(x-240)^3) % Use this equation
end
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Accepted Answer
VBBV
on 24 Feb 2023
x = 2:1000;
y = piecewise(x)
function y = piecewise(x)
for k = 1:length(x)
if (x(k)>0) & (x(k)<=120) % for 0 < x <= 120
y(k) = ((800*x(k)^3)-(13.68*(10^6)*x(k))-(2.5*x(k)^4)); % Use this equation
elseif (x(k)>120) & (x(k)<=240) % for 120 < x <= 240
y(k) = ((800*x(k)^3)-(13.68*(10^6)*x(k))-(2.5*x(k)^4)+2.5*(x(k)-120)^4); % Use this equation
elseif (x(k)>240) & (x(k)<=360) % for 240 < x <= 360
y(k) = ((800*x(k)^3)-(13.68*(10^6)*x(k))-(2.5*x(k)^4)+2.5*(x(k)-120)^4+600*(x(k)-240)^3); % Use this equation
end
end
end
2 Comments
VBBV
on 24 Feb 2023
you can use a for loop inside the function, and access the elements inside the input vector. However, when you dont use for loop it will compare the condition only once, which when not satisfied will result in error.
Stephen23
on 24 Feb 2023
Probably one should avoid shadowing the symbolic toolbox function:
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