Converting string to integer - indexing and multiple trials
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I have 120 trials in one Matlab file, all trials are separate within the file and look similar to that of trial1.mat (attached). I am importing this Matlab file into Python and indexing into the correct spot with
cue_times = trial(['BehavioralCodes']['CodeTimes'], dtype=int)
**I know this is not a Python platform, and that is not my question, I am merely explaining what I'm doing when I get the error I am getting.**
I get the error that the list indices must be integers or slices, not str
I need to convert 'CodeTimes' within 'BehavioralCodes' in each trial (each trial is saved individually like trial1) from a string to an integer.
I have tried:
code_times = str2num('CodeTimes') but that gives me an empty array so I am definitely doing something wrong.
I am not sure how to index into the correct space and then to include all trials (perhaps a for loop?). Any help would be greatly appreciated!
Accepted Answer
If you look into your data in Matlab, you will see that CodeTimes is actually an array of doubles and not strings:
cc = load (websave('trial1.mat', 'https://www.mathworks.com/matlabcentral/answers/uploaded_files/1315225/trial1.mat'));
code_times = cc.Trial1.BehavioralCodes.CodeTimes;
code_numbers = cc.Trial1.BehavioralCodes.CodeNumbers;
vpa(code_times(1:5),6) % show first 5 elements
code_numbers (1:5)
% check type
class(code_times)
class(code_numbers)
In Matlab you can use function round to round to the neareast integer:
code_times_int = round(code_times);
code_numbers_int = round(code_numbers);
% show first 5 elements
code_times_int(1:5)
code_numbers_int(1:5)
If round is not what you want, then check
help floor
help ceil
3 Comments
Antoinette Burger
on 5 Mar 2023
Edited: Antoinette Burger
on 5 Mar 2023
This loop will give you an answer (assuimg the name is trialX.mat)
for i = 1:120 % assuming 120 files in total
filename = ['trial', num2str(i), '.mat']; % form filename
% load filename and perform processing like already described
fprintf('%s\n',filename)
end
Antoinette Burger
on 5 Mar 2023
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