finding a numeric pattern in an array

12 views (last 30 days)
Hi all,
I have a big numeric vector and I am trying to find a pattern in the vector.
Example:
my numeric vector = [11 5 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 11 2 31 5 1 2 11 2 31 5 1 2 11 2 31 5 1 2 11 2 31 5 1 2 11 2 31 5 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 11 2 31 5 1 2 11 2 31 5 1 2 11 2]
pattern : [1 2 3 4 5 *any numbers* 1 2 3 4 5 1 2 11 2 31]
I know strfind works well if I know the exact sequence of pattern. But for the above case I am unable to find the solution.

Accepted Answer

Stephen23
Stephen23 on 27 Mar 2023
Edited: Stephen23 on 27 Mar 2023
V = [11,5,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,11,2,31,5,1,2,11,2,31,5,1,2,11,2,31,5,1,2,11,2,31,5,1,2,11,2,31,5,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,3,4,1,2,3,4,5,1,2,3,4,5,1,2,3,4,5,1,2,11,2,31,5,1,2,11,2,31,5,1,2,11,2]
V = 1×133
11 5 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5
F = @(v) regexptranslate('escape',char(v));
P = sprintf('%s.*?%s',F([1,2,3,4,5]),F([1,2,3,4,5,1,2,11,2,31]))
P = '□□□□□.*?□□□□□□□□□□'
[X,Y,M] = regexp(char(V),P, 'start','end','match') % start & end indices, matched text.
X = 1×2
6 64
Y = 1×2
35 122
M = 1×2 cell array
{'□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□'} {'□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□'}
Checking the matched content:
double(M{1})
ans = 1×30
1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 11 2 31
double(M{2})
ans = 1×59
1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5
  3 Comments
Stephen23
Stephen23 on 27 Mar 2023
Edited: Stephen23 on 27 Mar 2023
"can't we just take char([1 2 3 4 5 '.*?' 1 2 3 4 5 1 2 11 2 31])?"
That should work the same as my original answer, but ... I realized that we also need to account for special characters that need escaping, so you might also need to use REGEXPTRANSLATE something like this:
F = @(v) regexptranslate('escape',char(v));
P = sprintf('%s.*?%s',F([1,2,3,4,5]),F([1,2,3,4,5,1,2,11,2,31]))
P = '□□□□□.*?□□□□□□□□□□'
I will update my answer with this.
Saikrishna
Saikrishna on 27 Mar 2023
@Stephen23 excellent! Thank you :) that worked for me perfectly

Sign in to comment.

More Answers (0)

Categories

Find more on Characters and Strings in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!