How to save the output value from struct H(Index).b to variable f ?
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Code:
Index=1;
if(H(Index).e > 0.5 && H(Index).c > 0.9 || H(Index).c < 0.5 && H(Index).en > 0.2 && (H(Index).x)>10)
f=H(Index).b;
fprintf("Embedding Region %d\n",f);
Index=Index+1;
Explain:
Actually the H struct has five field and based on the if condition it display the output correctly but the issue is, all the values is not stored in variable ' f ', only the last value is shown as f value? How to store all the selected values to the variable f? If i declare f as array then also the last value is alone store in f? where am lagging am not getting? Can anybody suggest solution.
Thanks in Adavnce.
3 Comments
Answers (1)
akshatsood
on 13 Oct 2023
Edited: akshatsood
on 13 Oct 2023
Hi Aberna,
I understand that you want to store the output from a struct 'H' into a variable 'f'. To achieve this, you need to declare the variable 'f' as a vector with the same size as 'H'. Based on the provided code snippet and the information given in the question, I have assumed the existence of a struct 'H' and prepared a script to guide you through the correct approach. Please refer to the code snippet attached herewith.
% create an empty struct array
H = struct('e', [], 'c', [], 'en', [], 'x', [], 'b', []);
% generating random values for each field
for i = 1:5
H(i).e = round(0.5+rand(1), 1);
H(i).c = round(1+rand(1), 1);
H(i).en = round(rand(1), 1);
H(i).x = round(10*rand(1), 1);
H(i).b = round(rand(1), 1);
end
% preallocating f to store the output
f = zeros(1,5);
Index = 1;
while Index <= 5
if (H(Index).e > 0.5 && H(Index).c > 0.9) || ((H(Index).c < 0.5 && H(Index).en > 0.2) ...
&& (H(Index).x > 10))
f(Index) = H(Index).b;
fprintf("Embedding Region %.1f\n",f(Index));
end
Index=Index+1;
end
Now, the variable 'f' will store the value corresponding to the field 'b' in the struct 'H'. Since the complete code was not provided, I have made assumptions to illustrate the correct methodologies. Update the above code as per your needs.
I hope this helps.
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