how to check if numbers in the vector is within range of 1:10

   while length(x) == 6
        if x < -36 && x > 47

If there was an input and I had to check if the values of the array is within the elements of 1:10, how can i do it?

I though just checking if the input of array was bigger or small than the limited number it works but it didn't.

I'm assuming you have to check either all at once or one by one.

could someone help me?

Thank you in advance =]

Answer 1

[Thorsten]

all(x >= 1 & x <= 10)

[GOENG]

     I got an error for this

       if all(inPut > -36 && inPut < 46)
                disp('Do it again, within -36 to 46, and size of 1 by 6: ');
                inPut = input('Please put a number within -36 to 46: ');
            else

error message: Operands to the and && operators must be convertible to logical scalar values.

i put in the vector of inPut = [55 55 55 55 55 44] so one of the number is within range and the other 5 isn't to check.

[James Tursa]

Thorsten used a single &, and you used a double &&. The single & is element-wise operator and the double && is intended for scalar operands only. Use a single &.

Answer 2

[Jan]

If the inputs are large, the creation of the temporary arrays consumes a lot of time. Then this MEX function is more efficient: FEX: anyExceed :

if anyExceed(x, 1, 10)

This avoids creating the temporary arrays t1 = x >=1 , t2 = x<=10 and t1&t2 and the code stops at the first matching element.

[GOENG]

unfortunately it has to be something built in only. No external files but thanks for the link, that really does make it simpler.