Any suggestion to replace the diagonal values of matrices in a 3D array?
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julian gaviria
on 6 Nov 2023
Commented: Dyuman Joshi
on 6 Nov 2023
Any suggestion to replace the diagonal values of matrices in a 3D array?
in case1 to "0"
in case1 to "NaN"
e.g. for NaN
M_3D=randi(100, 4,4,3); %fake input
N=size(M_3D,1);
mask=1:N+1:end)=nan;
M_3D=M_3D.*mask;
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Steven Lord
on 6 Nov 2023
One possibility is points at subscripts n*ones(1, ndimsOfArray) for n = 1:min(size(theArray)). Once you reach any "edge" of the array you stop.
So for an array of size (4, 3, 5) those would be the elements at subscripts (1, 1, 1), (2, 2, 2), and (3, 3, 3). That matches conceptually the behavior of the diag function on non-square matrices.
A = reshape(1:12, 3, 4)
diag(A) % (1, 1), (2, 2), and (3, 3) since min(size(A)) is 3.
Accepted Answer
Dyuman Joshi
on 6 Nov 2023
Replacing diagonal values of each 2D matrix of a 3D matrix with NaN
M = randi(100, 4,4,3); %fake input
N = eye(size(M,[1 2]));
M(M&N)=NaN
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