Newton methods for solving nonlinear
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Please help me fix this code programe
main()
function main()
X0 = [25; 20; 4; 1];
% Áp dụng phương pháp Newton
X = newtons_method(X0)
% Hiển thị kết quả
disp('Kết quả:')
disp(['Nhiệt độ nước lớn nhất là: ', num2str(X(1))]);
end
function F = equations(X)
F = [X(1) - (X(2) + 0.5 * X(3) - 0.2 * X(4));
X(2) - 20;
X(3) - 5;
X(4) - 2];
end
function J = jacobian(X)
J = [1, -0.5, -0.1, 0.2;
0, 1, 0, 0;
0, 0, 1, 0;
0, 0, 0, 1];
end
function X = newtons_method(X0)
% Phương pháp Newton
max_iterations = 100;
tolerance = 1e-6;
X = X0;
for i = 1:max_iterations
F = equations(X);
J = jacobian(X);
delta_X = -J \ F;
X = X + delta_X;
if norm(delta_X, inf) < tolerance
break;
end
end
end
8 Comments
Torsten
on 15 Nov 2023
Ok, the first row of your Jacobian is wrong and your system of equations is a linear one so that you could have solved it easier than with Newton's method, but the iteration converges. So what exactly is your question ?
Khai
on 15 Nov 2023
Khai
on 15 Nov 2023
Torsten
on 15 Nov 2023
We have enough problems in the world - why inventing a new one ?
John D'Errico
on 15 Nov 2023
Your "solver" works. At least it does on the trivial example problem you chose, which is purely linear, so it will "converge" in one iteration. So where is the problem?
Khai
on 16 Nov 2023
Khai
on 16 Nov 2023
Answers (0)
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