warning all the time, don't know what is wrong
2 views (last 30 days)
Show older comments
syms m n p a x y z lambda real
g = x + y + z -a;
L = (x).^m.*(y).^n.*(z).^p - lambda.*g
Lx = diff(L,x)
Ly = diff(L,y)
Lz = diff(L,z)
sol = solve([Lx==0,Ly==0,Lz==0,g==0],[x y z lambda])
sol.x
sol.y
sol.z
Answers (1)
Walter Roberson
on 22 Mar 2024
Moved: Walter Roberson
on 22 Mar 2024
The 0^n and 0^(m-1) occur because there are not constraints on m and n, so there is the possibility that 0^0 is being generated, and 0^0 is 1 whereas 0^anything_else is 0
syms m n p a x y z lambda real
g = x + y + z -a;
L = (x).^m.*(y).^n.*(z).^p - lambda.*g;
Lx = diff(L,x);
Ly = diff(L,y);
Lz = diff(L,z);
eqns = [Lx==0,Ly==0,Lz==0,g==0];
partial_lambda = solve(eqns(1), lambda, 'returnconditions', true);
%partial_lambda.conditions
eqns2 = subs(eqns(2:end), lambda, partial_lambda.lambda);
partial_x = solve(eqns2(3), x);
eqns3 = subs(eqns2([1:2 4:end]), x, partial_x);
partial_y = solve(eqns3(1), y, 'returnconditions', true);
%partial_y.y
%partial_y.conditions
eqns4 = subs(eqns3(2:end), y, partial_y.y);
syms parameter1 parameter2 real
partial_z1 = subs(solve(eqns4(1,1), z, 'returnconditions', true), sym('x'), parameter1);
partial_z2 = subs(solve(eqns4(2,1), z, 'returnconditions', true), sym('x'), parameter2);
partial_z3 = solve(eqns4(3,1), z, 'returnconditions', true);
%partial_z3.z
%partial_z3.conditions
back_z1 = partial_z1.z;
back_y1 = subs(partial_y.y(1), z, back_z1);
back_x1 = subs(partial_x, {y, z}, {back_y1, back_z1});
back_lambda1 = subs(partial_lambda, {x, y, z}, {back_x1, back_y1, back_z1});
solution1 = [x == back_x1, y == back_y1, z == back_z1, lambda == back_lambda1.lambda]
back_z2 = partial_z2.z;
back_y2 = subs(partial_y.y(2), z, back_z2);
back_x2 = subs(partial_x, {y, z}, {back_y2, back_z2});
back_lambda2 = subs(partial_lambda, {x, y, z}, {back_x2, back_y2, back_z2});
solution2 = [x == back_x2, y == back_y2, z == back_z2, lambda == back_lambda2.lambda]
back_z3a = partial_z3.z(1);
back_y3a = subs(partial_y.y(3), z, back_z3a);
back_x3a = subs(partial_x, {y, z}, {back_y3a, back_z3a});
back_lambda3a = subs(partial_lambda, {x, y, z}, {back_x3a, back_y3a, back_z3a});
solution3a = [x == back_x3a, y == back_y3a, z == back_z3a, lambda == back_lambda3a.lambda]
back_z3b = partial_z3.z(2);
back_y3b = subs(partial_y.y(3), z, back_z3b);
back_x3b = subs(partial_x, {y, z}, {back_y3b, back_z3b});
back_lambda3b = subs(partial_lambda, {x, y, z}, {back_x3b, back_y3b, back_z3b});
solution3b = [x == back_x3b, y == back_y3b, z == back_z3b, lambda == back_lambda3b.lambda]
back_z3c = partial_z3.z(3);
back_y3c = subs(partial_y.y(3), z, back_z3c);
back_x3c = subs(partial_x, {y, z}, {back_y3c, back_z3c});
back_lambda3c = subs(partial_lambda, {x, y, z}, {back_x3c, back_y3c, back_z3c});
solution3c = [x == back_x3c, y == back_y3c, z == back_z3c, lambda == back_lambda3c.lambda]
5 Comments
Dyuman Joshi
on 29 Mar 2024
Accepting the answer indicates that your problem has been solved (which can be helpful to other people in future) and it awards the volunteer with reputation points for helping you.
You can accept only 1 answer for a question, but you can vote for as many answers as you want. Voting an answer also provides reputation points.
See Also
Categories
Find more on Equation Solving in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!