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Generate Array of Random Values

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William Stewart
William Stewart on 6 Apr 2024 at 18:24
Answered: Stephen23 on 6 Apr 2024 at 19:14
I am trying to write a function to generate an array of random values as follows:
I have as inputs an array Dims (X by 2) and the number of samples per row Iter.
I need to create an X by Iter array where each row n in the array has uniformly distributed random values between Dims(n,1) and Dims(n,2).
I am trying to do this in an efficient way.
So far I have
Values = rand(size(Dims, 1), Iter);
for i = 1:size(Values, 1)
for j = 1:Iter
Values(i,j) = Values(i,j) * ((Dims(i,2) - Dims(i,1)) + Dims(i,1);
end
end
Is there a better way to do this?

Answers (2)

Voss
Voss on 6 Apr 2024 at 19:11
Dims = [5 10; 10 20; 30 100];
Iter = 6;
Values = rand(size(Dims,1),Iter).*(Dims(:,2)-Dims(:,1))+Dims(:,1)
Values = 3x6
7.9777 9.1161 8.4292 7.2950 8.1792 5.7199 13.2348 16.3659 13.7126 16.5311 16.6468 17.8477 48.4766 33.9438 74.4127 84.5108 78.5795 69.8849
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Stephen23
Stephen23 on 6 Apr 2024 at 19:14
D = sort(randi([-9,9],7,2),2)
D = 7x2
-9 -7 -2 6 -4 0 -9 -7 -7 5 -7 9 -9 -8
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V = rand(7,13);
V = V.*diff(D,1,2)+D(:,1)
V = 7x13
-8.6414 -7.8458 -8.8766 -7.9022 -8.7745 -7.6785 -7.2711 -8.2223 -8.5587 -8.1508 -7.9310 -8.6058 -7.8533 -0.4894 4.2643 2.9174 2.2213 2.5891 4.0897 1.6806 -0.2124 -1.1980 5.8553 5.3818 -1.6089 0.4423 -1.3513 -3.7748 -3.8460 -1.6601 -2.1304 -2.0749 -2.8700 -3.6019 -2.0163 -3.7580 -1.0548 -0.1917 -1.7693 -8.8450 -7.0183 -7.2684 -7.2548 -7.5254 -7.4451 -8.4325 -8.5864 -7.1123 -8.1188 -8.9025 -8.2176 -7.4825 -3.9550 -5.5765 -1.1027 -1.9687 -4.5128 -3.0736 1.1153 4.9786 3.7718 -0.5216 3.8545 0.4611 -5.0082 2.0961 -6.3508 0.0811 -4.5284 -2.3581 -3.5695 4.9573 1.0495 2.5981 6.2377 -1.2204 -1.5779 0.0114 -8.0202 -8.6069 -8.1219 -8.1449 -8.7622 -8.5805 -8.6816 -8.7140 -8.5465 -8.5408 -8.6633 -8.1803 -8.0489
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