Creating matrix from a for loop

I have this 'for loop' (where A a matrix from my program):

for m=symbols(1:1000)

d1=abs(m-A);
[C,I]=min(d1);
k=A(I);

end

I want from this loop to save the values of 'k' (1000 total) to a (1, 1000) matrix? How can I do this because I am getting some errors!

Thank you...

Answer 1

[Sven]

Hi athpapa,

I don't know what your "A" matrix or "symbols" matrix had, so I will just make them random numbers:

A = randi(500, 10) - 250;
symbols = randi(30,1,1000);

Now, we can make "k" as a vector of numbers (rather than just a single number). Note that I use "i" to iterate from 1:1000 so that we know which element of "k" to save our answer to:

k = zeros(1,1000);
for i = 1:1000
    m = symbols(i);
    d1=abs(m-A);
    [C,I]=min(d1(:));
    k(i) = A(I);
end

Does this do what you wanted it to do?

[athpapa -]

thanx!!This worked for me..

Do you know if I have a matrix that I use it like an index, for example: A=[1 3 2 4 1 3] which points to a matrix which represents binary bits B=[00 01 11 10]; How can I produce these bits? I mean I want: C=B(1) gives me 00, C=B(2) gives me 01 and so on...

[Sven]

The issue here is *all* about how to store "B", because the way you have it:

B=[00 01 11 10]

will not actually store the "binary bit" aspect - it will just convert it to numbers:

B=[0 1 11 10]

You can try perhaps defining "B" as a cell array of strings:

B={'00' '01' '11' '10'}

In which case I think it will work how you intended:

B([1 3 2 4 1 3])

If this doesn't quite answer you question, it's a good idea to make a new question and post it (since this is off-topic from the original)

[Walter Roberson]

dec2bin(A,2) - '0'