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Stl file pdegplot in App designer

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Jigar
Jigar on 17 May 2024
Edited: Cris LaPierre on 20 May 2024
Hi,
I am looking for a solution to find names of the faces after importing the stl file. pdegplot command does that but how can I use it in App Designer. I am trying the command but it throws different error. Looked for a solution but it isn't available.
Is there any other command where i can use it to see name faces in the App designer so that i can use it to apply BC.
Thanks,
Jigar
  1 Comment
Cris LaPierre
Cris LaPierre on 17 May 2024
What error are you getting? Please share all the red text.

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Accepted Answer

Adam Danz
Adam Danz on 17 May 2024
Edited: Adam Danz on 17 May 2024
> pdegplot command does that but how can I use it in App Designer?
pdegplot does not have an input argument or property to specify the parent axes. This often poses a propblem in AppDesigner and uifigures in general since the default HandleVisible property in uifigures is 'off'. This prevents pdegplot from finding the axes within the uifigure resulting in the generation of a new figure external to the app.
I suppose this is the problem you're running into.
This workaround describes how to temporarily make the app's axes accessible and current so that the pdegplot will add content to the existing axes.
Here's a quick example. See the previous link for details.
% Mimick an app
app.UIFigure = uifigure();
app.UIAxes = uiaxes(app.UIFigure);
% Change handle visibility
origState = app.UIFigure.HandleVisibility;
handleVisCleanup = onCleanup(@()set(app.UIFigure,'HandleVisibility',origState));
app.UIFigure.HandleVisibility = 'on';
% Make axes current
set(groot, 'CurrentFigure', app.UIFigure)
set(app.UIFigure,'CurrentAxes',app.UIAxes)
% Plot pdegplot
g = [2 1 1 1 1 1 1 1 1 4 4;
-1 -0.6 -0.5 -0.4 -0.5 0.4 0.5 0.6 0.5 -1 0.17;
1 -0.5 -0.4 -0.5 -0.6 0.5 0.6 0.5 0.4 0.17 1;
0 -0.25 -0.35 -0.25 -0.15 -0.25 -0.35 -0.25 -0.15 0 -0.74;
0 -0.35 -0.25 -0.15 -0.25 -0.35 -0.25 -0.15 -0.25 -0.74 0;
0 0 0 0 0 0 0 0 0 1 1;
1 1 1 1 1 1 1 1 1 0 0;
0 -0.5 -0.5 -0.5 -0.5 0.5 0.5 0.5 0.5 0 0;
0 -0.25 -0.25 -0.25 -0.25 -0.25 -0.25 -0.25 -0.25 0 0;
0 0.1 0.1 0.1 0.1 0.1 0.1 0.1 0.1 1 1;
0 0 0 0 0 0 0 0 0 0.75 0.75;
0 0 0 0 0 0 0 0 0 0 0];
pdegplot(g)
  10 Comments
Jigar
Jigar on 19 May 2024
Edited: Jigar on 19 May 2024
editing
I take my words back. It is working with an app property. Thanks for all the help!
Adam Danz
Adam Danz on 20 May 2024
Glad that it all worked out, thanks for the demo @Cris LaPierre!

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