I didn't understand it how they completed it?

4 views (last 30 days)
  2 Comments
John D'Errico
John D'Errico on 4 Aug 2024
Please stop posting your homework questions with no effort made. Future questions like this will be closed as soon as I see them, if you cannot make an effort. Homework is yours to do.
Sam Chak
Sam Chak on 4 Aug 2024
It appears that you have two open questions that have been answered, but you have not followed up to provide an update. Instead, you have opened a third homework question. I would encourage you to take some time to review the solutions provided for the other two homework questions:
By reviewing the provided solutions, you may gain a better understanding of how to approach and complete these types of problems in MATLAB. Taking the time to thoroughly understand the previous solutions can help you make progress on your current homework question.

Sign in to comment.

Answers (1)

VBBV
VBBV on 4 Aug 2024
Edited: VBBV on 4 Aug 2024
@Mohit Define the symbolic variables d & theta for the given equation to be solved
%
syms d theta
x = [d theta]; % define a symbolic vector of unknown variables , depth (d) and theta
fminsearch(@f,[25 1.5]) % give initial values based on the answer options and solve using fminsearch
ans = 1x2
14.8119 1.0472
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
% use explicit function call
function y = f(x)
y = 380./x(1) - x(1)/tan(x(2)) + 2*x(1)/sin(x(2));
end
  1 Comment
Walter Roberson
Walter Roberson on 5 Aug 2024
Edited: Walter Roberson on 5 Aug 2024
? Defining the symbolic variables does not appear to do anything useful here??
Maybe if you had used
syms d theta
x = [d theta]; % define a symbolic vector of unknown variables , depth (d) and theta
f(x)
ans = 
fminsearch(@f,[25 1.5]) % give initial values based on the answer options and solve using fminsearch
ans = 1x2
14.8119 1.0472
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
% use explicit function call
function y = f(x)
y = 380./x(1) - x(1)/tan(x(2)) + 2*x(1)/sin(x(2));
end

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!