how do I load zip file in matlab code?

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kuldeep
kuldeep on 12 Sep 2024
Edited: Walter Roberson on 12 Sep 2024
for i = 1:length(files)
file = fullfile('c:\sar', files(i).name);
disp(file);
% Load and preprocess the data
source = loadProduct(file); % Define or replace this function with actual data loading
it gives following errors
>> SAR_preprocessing
c:\sar\S1A_IW_GRDH_1SDV_20240823T005527_20240823T005552_055333_06BF4D_21CD.SAFE.zip
Error in SAR_preprocessing>main (line 44)
source = loadProduct(file); % Define or replace this function with actual data loading
Unrecognized function or variable 'loadProduct'.
Please suggest me how to load zip file for further processing.
Kuldeep

Answers (2)

Voss
Voss on 12 Sep 2024

Use unzip to extract the files from the zip archive. Then read/load the relevant extracted files using the appropriate function(s), e.g. readmatrix.


Epsilon
Epsilon on 12 Sep 2024
Hi Kuldeep,
The above error is being produced as the function loadProduct used is not a defined MATLAB function. To extract a zip file you can use the ‘unzip’ function and then load the files from the extracted location.
Here is an exemplar attached code to extract and load/open files after extracting a zip file:
% Unzip the file unzip('zipFileName','extractDir')
unzip('C:\Folder\zipped.zip','C:\Folder\Extracted')
%cd to extracted Directory
cd 'C:\Folder\Extracted\'
% Extract list of all files in the directory/subdirectory
files = dir ("**");
%convert the struct to a table for indexing
filesTable=struct2table(files);
for i = 1:height(filesTable)
%Get full File path of each file
filePath = fullfile(filesTable.folder{i}, filesTable.name{i})
%check extension Type
[~, ~, ext] = fileparts(filePath);
%switch acc. to extension types
switch ext
% open different file types or load
case '.m'
open (filePath);
case'.mat'
load (filePath);
% add other extensions here as needed
end
end
You can use the above code and make changes to it for your use.
Also, for reference here are the links to the used MATLAB functions:

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R2024a

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